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The cell outlined in red is the only cell sticking out of all cages that belong to the first 5 columns. So it’s value must be: (Sum of All Cages in First 5 Columns) – 5*45. In this case it equates to: (4+9+15+28+10+17+21+12+14+7+24+11+12+21+14+13)-5*45 = 232 – 225 = 7. Of course you could’ve done it the other way – as an innie of the last 4 columns. And remember – whenever you find an innie/outie in a symetrical puzzle, there’s always one more – exactly opposite to the one you just found. I hope you see which one I’m talking about. It’s a coincidence that in this puzzle the value of the opposite innie/outie is identical (it’s also 7). Once you solve those two and solve the two cells in the upper left corner, there’s nothing fancy about yesterday’s puzzle :).
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Please, I need an answer Â¿Is it possible to have the same number inside a box which is between two nonets? For example, the 16 between the two upper right nonets. Should it be a 7, 7 & 2?
Agueda, there has been some discussion regarding this on this and other sites too.
Basically, my puzzles CAN NOT have two occurrences of the same number inside one “cage”, even if that is allowed by other Sudoku rules.
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[…] technique is somewhat similar to innies/outies which is used for solving Killer Sudoku puzzles, but there is no math involved and, again, it […]