Here is an explanation of a Hidato solving technique that some people might find obvious and they use it without even thinking of it as a special technique. But, for those who still struggle with the more difficult

puzzles, here is a quick guide of the technique that I call “

**cornering**“.
It can be used when a cell has only one â€œ

**neighbor**â€ that is an empty cell. In such a case, that cell (with only one empty neighbor), must contain a number that is consecutive to (at least) one of the already filled in neighbors.

Look at the upper left corner. Number 33 could in theory go into any of the 4 cells that are neighbors to both 32 and 34. However,

**it must actually go into R1C1** (row 1, column 1).

**Why**? Because R1C1 has only one empty neighbor and according to the rule I stated above, in such a case that cell must be consecutive to (at least) one of the existing neighbors.

**Why**? Because each cell (other than 1 and the largest number) must have both a â€œ+1â€ and a â€œ-1â€ neighbor. So, the only options for R1C1 are 31 or 33 or 35. If you put any number other than one of those in R1C1, it would have only one of the â€œ+1â€, â€œ-1â€ neighbors, because there is only room for one number next to it. That is why I also call this technique â€œ

**dead-end**â€. But 31 would be too far from 29; and 35 would be too far from 39.

**Therefore R1C1=33!**
Now, look at R1C7 (itâ€™s circled). See if you can figure out why the number in that cell MUST BE 5.

### Like this:

Like Loading...

*Related*

## 2 Comments

Just a thought, could you make a “Greater Than/Less Than” Hidoku and use very few given numbers?

Yes Amy! 🙂 It is possible and I’ve been thinking about the same thing but just can’t find time right now to do it… will be done next year, though.